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Shalnov [3]
3 years ago
7

Add the following weights: 5 lb 9 oz + 1 lb 9 oz Ib OZ

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
Answer: 7lb 2oz

have a great day :)
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Y=4x+1 <br> Do x and y vary directly?
vladimir1956 [14]
<span>Slope = 8.000/2.000 = 4.000 
x-intercept = 1/-4 = -0.25000<span> 
y-intercept = 1/1 = 1.00000

</span></span> <span> y-(4*x+1)=0 </span>
6 0
3 years ago
Kevin has 2/5 of a pound of candy. 3/10 of the candy is chocolate. How many pounds of chocolate does he have?
ehidna [41]
3 is the answer for it
8 0
3 years ago
Ten less than 5 times the value of a number is equal to 10 times the quantity of
grandymaker [24]

Answer:

52

Step-by-step explanation:

given that the number is a

The expression for Ten less than 5 times the value of a number is given by

5a - 10

10 times the quantity of  12 more than one-fourth of the number.

a/4 is one-fourth  of number

12 more than one-fourth of the number

a/4 + 12

expression for  10 times the quantity of  12 more than one-fourth of the number. is given by

10(a/4 + 12) = 10a/4 + 12*10 = 2.5a + 120

Given that the above two expression are equal

equating them we have

5a - 10 = 2.5a + 120

adding 10 both sides

=>5a - 10+ 10  = 2.5a + 120 + 10

=> 5a = 2.5a + 130

subtracting 2.5a from both sides

=> 5a - 2.5a = 2.5a + 130 - 2.5a

=> 2.5a = 130

dividing both side by 2.5

=> a = 130/2.5 = 52

Thus, value of a is 52

5 0
3 years ago
A catering service offers
Fiesta28 [93]

Answer:

There are 52920 ways to do the banquet

Step-by-step explanation:

* Lets revise the combination to solve this problem

- A combination is a collection of the objects where the order

 doesn't matter

- The order is not important in this problem, so we can use the  

  combination nCr to find how many ways can this done

* Lets solve the problem

- A catering service offers 6 appetizers, 7 main courses, 10 desserts.

- A customer is to select 5  appetizers,  4  main courses, 5  desserts

 for a banquet

∵ We want to select  5  appetizers from 6

∴ There are 6C5 ways to chose the appetizers

∵ 6C5 = 6

∴ There are 6 ways to chose the appetizers

∵ We want to select  4  main courses from 7

∴ There are 7C4 ways to chose the main courses

∵ 7C4 = 35

∴ There are 35 ways to chose the main courses

∵ We want to select  5  desserts from 10

∴ There are 10C5 ways to chose the desserts

∵ 10C5 = 252

∴ There are 252 ways to chose the desserts

- To find the number of ways to do the banquet multiply all the

  answers above

∵ The total ways = 6C5 × 7C4 × 10C5

∴ The total ways = 6 × 35 × 252 = 52920

* There are 52920 ways to do the banquet

5 0
3 years ago
Please help im gonna scream im so confuesed :(
iren [92.7K]

Answer:

14^{-17}

Step-by-step explanation

using the rules of exponents,  it would be 14^{10}÷14^{27} so then take away 27 from 10 and get -17 meaning that the answer would be A or 14^{-17}

5 0
3 years ago
Read 2 more answers
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