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adell [148]
3 years ago
7

Solve 3x2 + 4x = −5.

Mathematics
1 answer:
Alla [95]3 years ago
4 0
Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

a=3
b=4
c=5

x=\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}
x=\frac{-4+/- \sqrt{16-60} }{6}
x=\frac{-4+/- \sqrt{-44} }{6}
x=\frac{-4+/- 2\sqrt{-11} }{6}
remember that√-1=i
x=\frac{-4+/- 2i\sqrt{-11} }{6}
x=\frac{-2+/- i\sqrt{-11} }{3}

x=\frac{-2+ i\sqrt{-11} }{3} or x=\frac{-2- i\sqrt{-11} }{3}


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guajiro [1.7K]

Answer:

9:34 pm

Step-by-step explanation:

First:

8:17 am

Go back 12 hours

8:17 pm

Round to 8:20

(keep the 3) Minus 43-17=26(3 is in this)

Therefore, 9:34 pm

Sorry if this doesn't make sense, it's hard to explain haha

7 0
2 years ago
What is the length of z? (Round to the nearest tenth)
navik [9.2K]

Answer:

<em>z = 10.8</em>

Step-by-step explanation:

9^{2} + 6^{2} = c^{2}

81 + 36 = c^{2}

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4 0
3 years ago
F (x )= 1/4 x for x = -5
Sholpan [36]

Answer:

-5/4

Step-by-step explanation:

f(x)=1/4x

f(-5)=1/4(-5)

f(-5)=-5/4

6 0
3 years ago
Read 2 more answers
Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func
mote1985 [20]

Solution:

The given Polynomial is :

f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})

By Rational Root theorem the  of Zeroes of the Polynopmial are:

\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4

But , f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5}).

8 0
3 years ago
Read 2 more answers
Hi ! please help !
tatuchka [14]

Hey there! I was looking at your question for a bit then realized you meant i, the imaginary number, not "1" at the end of each number.

  • Complex numbers are numbers involving both real and imaginary numbers; thus, this question wouldn't make much sense without the imaginary number i

The expression we are given is:

(3+4i)+(8+2i)

Open parenthesis and combine like terms:

=3+4i+8+2i

=11+6i

This is answer choice B (assuming it's supposed to be an i and not a "1" at the end)

Let me know if you need any clarifications, thanks!

~ Padoru

5 0
3 years ago
Read 2 more answers
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