Answer:
2
Step-by-step explanation:
1/3 plus 1/3 =2/6 then you do 2/6 plus 2/6 and get 4/6 then you cant do 4/6 plus 4/6 because it will be bigger than 5/6
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
C = 2(3.14) x r
C = 6.28 x 10
C = 62.8 yards
D- 4 is your correct answer :)
Hope this helps
