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Yakvenalex [24]
2 years ago
10

Nora uploaded a funny video on her website, which rapidly gains views over time. The relationship between the elapsed time, ttt,

in days, since Nora uploaded the video, and the total number of views, V(t)V(t)V, left parenthesis, t, right parenthesis, is modeled by the following function: V(t)=100⋅(1.53)t Complete the following sentence about the daily rate of change in the views of the video.
Mathematics
1 answer:
inysia [295]2 years ago
7 0

Answer:

grows by a factor of 1.53

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Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th
bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0
3 years ago
- Trevon invested $1.500 in an account with an interest rate of 4.25%. If he plans to retire in 18 1/2 years, how much total wil
gizmo_the_mogwai [7]

Answer:

I=PRT is the formula

Step-by-step explanation:

Principal is $1,500. The interest rate is 4.25% and the time is 18.5 years.

That's all i know good luck

5 0
2 years ago
Hannah has another candle that is 14 cm tall. How fast must it burn in order to also be 6 cm tall after 4 hours? Explain your th
RideAnS [48]

Answer:

The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.

Step-by-step explanation:

Lets solve!

We have to find out how much of the candle needs to be burned!

14cm - 6cm = 8cm

The candle must burn 8cm in 4 hours!

Lets find out how much the candle burns in 1 hour.

\frac{8cm}{4hours}= 2cm per hour

The candle must burn at 2cm per hour in order to be 6cm tall after 4 hours. I know this because the candle has to burn 8cm in 4 hours and that amounts to 2cm per hour.

Woohoo, We did it! <u>Would you like to mark my answer as brainliest?</u> I would love that!

6 0
2 years ago
What is the area of this composite shape?
grandymaker [24]

(29-22)*26+(26-21)*22

Cut the figure into 2 then find the unknown lengths to find each part. Add them together, and you'll get the answer.

4 0
3 years ago
They randomly survey 50 students about how much money they spend on lunch each day. What is the expected value for a student to
siniylev [52]
2$ for public 3-4$ for private
3 0
3 years ago
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