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mr_godi [17]
3 years ago
14

I need help I'm confused.

Mathematics
1 answer:
swat323 years ago
3 0

Answer:

ok

Step-by-step explanation:

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If your car goes 50 kilometers in 2 hours,what is its average speed
Georgia [21]

Answer:

25 kilometers per hour

Step-by-step explanation:

I just simply made it into a proportion of 50/2=x/1 and 50 divided by 2 is 25. hopefully that help you.

8 0
3 years ago
Which is more, 1 quart or 7 cups?<br><br> A. 1 quart<br> B. 7 cups<br> C. neither; they are equal
cricket20 [7]
1 quart is equal to 4 cups so the answer is B.
5 0
3 years ago
Read 2 more answers
What is -2(3X +12 Y -5-17 X -16 Y +4) Simplified
notsponge [240]

Answer:

-2 (3x +12 Y -5 -17 X -16 Y +4)

Step-by-step explanation:

omg.. here we go..

-2 (17) i THinK im not sure hope this helped

7 0
3 years ago
Please show your work
rjkz [21]

Answer:

52

Step-by-step explanation:

If JK bisects the angle, the two angles are equal

6x+2 = 8x-6

Subtract 6x from each side

6x-6x+2 = 8x-6x-6

2 = 2x-6

Add 6 to each side

2+6 =2x-6+6

8 =2x

Divide by 2

8/2 =2x/2

4 =x

Now find angle LJM, which is the sum of the two angles

6x+2 + 8x-6

14x -4

14*4-4

56-4

52

5 0
3 years ago
Read 2 more answers
The given line passes through the points (0, -3) and (2, 3).
puteri [66]

The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }

\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}

Hence, the line equation is y + 1 = 3(x + 1).

6 0
3 years ago
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