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kenny6666 [7]
2 years ago
7

Which equation in slope-intercept form represents a line that passes through the point (2,3) and is

Mathematics
1 answer:
VLD [36.1K]2 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

Which equation in slope-intercept form represents a line that passes through the point (2,3) and is perpendicular to the line y−9=23(x+7)

Solution:

The equation of a line in slope intercept form is given as y = mx + b, where m is the slope and b is the y intercept.

Given a line y−9=23(x+7)

y - 9 = 23x + 161

y = 23x  + 170. The slope of this line comparing with y = mx + b gives m = 23

Two lines are perpendicular if the product of their slope gives -1.

Let m_1 be the slope of the perpendicular line, hence:

m_1(23)=-1\\\\m_1=\frac{-1}{23}

Since the perpendicular line passes through (2, 3), we can get its equation using:

y-y_1=m_1(x_x_1)\\\\y-3=\frac{-1}{23}(x-2)\\\\y= \frac{-1}{23}x+\frac{2}{23}+3\\\\   y= \frac{-1}{23}x+\frac{71}{23}

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Answer:

(x+7) is not a factor

Step-by-step explanation:

we know that

If (x+7) is a factor of f(x)

then

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Verify

we have

f(x)=x^{3}-3x^{2} +2x-8

Substitute x=-7

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f(-7)=--512

-512\neq 0

therefore

(x+7) is not a factor

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given the lines

-2x-3y=9

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Writing the equations in the slope-intercept form

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As

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