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natima [27]
3 years ago
12

Which of the following has more energy than visible light?

Chemistry
1 answer:
Svetlanka [38]3 years ago
6 0
It should be radio waves. If you need anymore help look up the wavelength chart online.

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Metric prefix name for 1/100 ?
babymother [125]
The metric prefix name for 1/100 is centimeters.
5 0
3 years ago
Calculate the mass of liquid with density of 3.3 g/mL and a volume of 25 oz
love history [14]

Answer: 215

Explanation:

Volume doesn’t add up into ounces that’s mass only

3 0
3 years ago
Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0
3 years ago
Electrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of
Aleonysh [2.5K]

Answer:

CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode

Explanation:

The valence of the elements in this case is as follows -

Cu - 2e-

Sn - 4e-

Cr - 3e-

CuSO4 cell will have the greatest amount of deposit among all three

The atoms of copper metal will deposit at the cathode. At the cathode, the least number of moles of electrons needed .

Hence, more amount of copper  can be extracted out by the electrolyte

 

3 0
3 years ago
Heyyyywooo Friends Can Yall Plz Help
VARVARA [1.3K]

Answer:

I think the answer is A

3 0
3 years ago
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