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mylen [45]
3 years ago
10

What is the definition of erosion? the process by which sediment settles out of water the soil and rocks deposited by moving wat

er the process by which a river moves soil and rock the waterways that move soil and rock
Chemistry
2 answers:
Travka [436]3 years ago
3 0

Answer:

Sediment moves from one place to another through the process of erosion. Erosion is the removal and transportation of rock or soil. Erosion can move sediment through water, ice, or wind. Water can wash sediment, such as gravel or pebbles, down from a creek, into a river, and eventually to that river's delta.

Explanation:

velikii [3]3 years ago
3 0

Answer:

it C

Explanation:

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Oxidation number of Ni in Ni(CO)4 is​
nikdorinn [45]

Answer:

0

Explanation:

answer from gauth math

5 0
2 years ago
Construct the inequality for the following cases.
Rudik [331]

Answer:

x + y < 50

Explanation:

8 0
2 years ago
Gasoline has a density of 0.749 g/ml. how many pounds does 19.2 gallons of gasoline weigh?
Svetradugi [14.3K]
A good first step is writing the amount in terms of ml. 

19.2 gallons = 72.68 L = 72680 ml

that would mean it weighs 0.749*720680g = 54437.32ml = 54.437 L

hope that helps :)
6 0
2 years ago
Read 2 more answers
The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in
nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  

W_s = weight of solvent in g  

Mole fraction of CO_2 is = 3.6\times 10^{-4} i.e.3.6\times 10^{-4}  moles of CO_2 is present in 1 mole of solution.

Moles of solute (CO_2) = 3.6\times 10^{-4}

moles of solvent (water) = 1 - 3.6\times 10^{-4} = 0.99

weight of solvent =moles\times {\text {Molar mass}}=0.99\times 18=17.82g

Molality =\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020

Thus  approximate molality of CO_2 in this solution is 0.020 m

5 0
3 years ago
Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

5 0
2 years ago
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