edgar divided a five digit number by two digit number there was no remainder what is the least possible quotient of the two numb
1 answer:
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Answer:
(1)Equivalence Relation
(2)Not Transitive, (0,3) is missing
(3)Equivalence Relation
(4)Not symmetric and Not Transitive, (2,1) is not in the set
Step-by-step explanation:
A set is said to be an equivalence relation if it satisfies the following conditions:
- Reflexivity: If
- Symmetry:
- Transitivity:
(1) {(0,0), (1,1), (2,2), (3,3)}
(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}
The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.
(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}
In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.
Therefore, It is not transitive.
As a result, the set (2) is not an equivalence relation.
(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}
(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric
Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.
Width = -3 + sqrt(159)
Length = 3 + sqrt(159)
Answer:
Square.
Step-by-step explanation:
given J(-4,2) || K(0,3) || L(1,-1) || M(-3,-2)
given below the visual answer.
OR
you can find the distance of coordinate to coordinate:
Distance of JK
√(-4-0)² + (2-3)²
√17
Distance of KL
√(0-1)²+(3--1)²
√17
Distance of LM
√(1--3)²+(-1--2)²
√17
Distance of MJ
√(-3--4)²+(-2-2)²
√17
All sides are similar of √17 , so its a square.
