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TiliK225 [7]
3 years ago
13

Describe how naturally acidic rainwater can affect a mountain of limestone.

Chemistry
1 answer:
Hitman42 [59]3 years ago
6 0
The naturally acidic rainwater will erode the limestone mountin over time
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Will be giving brainliest for correct answer.
vova2212 [387]

Answer:

The balanced chemical equation is Pb(NO3)2 + 2KI produces PbI2 + 2K(NO)3. In chemistry, this is called a double replacement reaction. Lead nitrate and potassium iodide, which are the reactants, are powders that react to form a yellow-colored lead iodide and a colorless potassium nitrate.

Explanation:

3 0
3 years ago
Read 2 more answers
What is the majority of a solution that contains 0.55 mole of HCl in water to make 1.50 L HCl solution?
PSYCHO15rus [73]

Answer:

0.367M

Explanation:

Molarity refers to the molar concentration of a solution. It can be calculated using the formula below:

Molarity = n/V

Where;

n = number of moles (mol)

V = volume (L)

According to the given information in this question;

n = 0.55 mole

V = 1.50 L

Molarity = 0.55/1.50

Molarity = 0.367M

4 0
3 years ago
Compare the arrangements of individual particles in solids, liquids, and gases?
salantis [7]
Solid particles are all compacted together, liquid particles are not as close as solid particles but still move together, and gas particles do not stay together

4 0
3 years ago
What is the hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4.
Maksim231197 [3]

The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

pH= -log[H+] - (i)

10^-3=H2So4

H+= 2×10-3

here ,

h2so4 ——— 2[H+] + so4^2-

thus [H+]= 2*10^(-3) because hydrogen ion has two moles

pH= -log[H+]

pH= -log(2×10^-3)

pH= 3-log2

pH= 3-log2pH= 2.7

The pH is 2.7

<h3>What is pH?</h3>

PH is the degree of alkalinity and acidicity in a solution.

Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7

Learn more about pH from the link below.

https://brainly.in/question/9937410

4 0
2 years ago
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of  CO = 0.35 mole

Volume of container = 1 L

Initial concentration of CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M

Initial moles of  H_2O = 0.40 mole

Volume of container = 1 L

Initial concentration of H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M

equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

                            CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

5 0
3 years ago
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