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sweet-ann [11.9K]
2 years ago
10

Hello :) how to do this?

Chemistry
2 answers:
Nina [5.8K]2 years ago
7 0

Answer:

i dk

Explanation:

juin [17]2 years ago
4 0

Answer:

28g/ dm³

0.5 M

Explanation:

1dm³= 1000cm³

Let's convert the volume to cm³.

Volume of solution

= 200cm³

= (200÷1000) dm³

= 0.2 dm³

Concentration in g/dm³ means the amount of solute, KOH, in 1 dm³ of solution.

In 0.2 dm³, there is 5.6g of KOH.

Thus in 1 dm³, amount of KOH

= 5.6 ÷0.2

= 28g

Concentration in g/dm³ is 28g/dm³.

Molarity is a concentration unit. It is the number of moles of solvent in 1 L or 1dm³ of solution. Since we have already found the mass of KOH in 1dm³ of solution, we will use dm³.

1dm³ ----- 28g of KOH

moles= mass ÷mr

Molecular mass of KOH

= 39 +16 +1

= 56

1dm³ ----- 28 ÷56= 0.5 moles of KOH

Thus, concentration in molarity is 0.5M.

(Unit for molarity is M)

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If you purchased 2.31 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?
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Answer:

8.547 x 10⁴disintegrations per second

Explanation:

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Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
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The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

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