All categories

3 years ago

What will happen if carbon dioxide is captured?

1 answer:

8 0

Carbon capture and storage, or carbon capture and sequestration and carbon control and sequestration, is the process of capturing waste carbon dioxide, transporting it to a storage site, and depositing it where it will not enter the atmosphere.

HOPE IT HELPS

FOLLOW MY ACCOUNT PLS PLS

You might be interested in

9.05 mol of oxygen gas to g of oxygen gas

NARA [144]

Molar mass of oxygen gas:

O₂ = 16 * 2 = 32.0 g/mol

1 mole O₂ -------------- 32.0
9.05 mole O₂ ---------- ?

Mass = 9.05 * 32.0

Mass = 289.6 g of O₂

hope this helps!

7 0

3 years ago

write a balanced chemical equation for each single replacement reaction that takes place in aqueous solution. write no reaction

Illusion [34]

The question is incomplete, here is the complete question:

Write a balanced chemical equation for each single replacement reaction that takes place in aqueous solution. write no reaction if a reaction does not occur

1.) Zn + PbCl₂

2.) Cu + Fe(NO₃)₂

Answer:

For 1: The reaction does occur.

For 2: The reaction does not occur.

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

$A+BC\rightarrow AC+B$

For the given options:

For 1:

Zinc is more reactive than lead as it lies above in the series. So, it will displace lead from its chemical equation.

The chemical equation for the reaction of zinc and lead chloride follows:

$Zn+PbCl_2\rightarrow ZnCl_2+Pb$

For 2:

Copper is less reactive than iron as it lies below in the series. So, it will not displace iron from its chemical equation.

The chemical equation for the reaction of copper and iron (II) nitrate follows:

$Cu+Fe(NO_3)_2\rightarrow \text{No reaction}$

3 0

3 years ago

Answer the lab question (“What is the effect of temperature on the solubility of a solid in a liquid?”) with a hypothesis:

valkas [14]

Explanation:

When experimenting, the best hypothesis to develop would be a null hypothesis (H₀). A null hypothesis is a statement indicating no change or effect. In this case, it would be;

“There is no effect of temperature on the solubility of a solid in a liquid”

An alternative hypothesis (Hₐ) would be;

“There is an effect of temperature on the solubility of a solid in a liquid”

In this experiment, the null hypothesis would be rejected and the alternative would be accepted. This is because the experiment would show that increased temperatures of the liquid increases solubility of the solid in the liquid.

8 0

3 years ago

Read 2 more answers

Anyone plz help?? T^T

Wewaii [24]

Answer:

C. Mg3N2

Explanation:

--------------

4 0

3 years ago

Read 2 more answers

For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)

juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = 4.82 grams benzene

Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

Mass CO2 = 9.15 grams

4 0

3 years ago