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Jlenok [28]
3 years ago
6

El agua de lluvia tiene un pH de 4,00. Calcule su concentración de ion hidrógeno en mol/litro. Explique por qué el agua es ácida

en lugar de neutra.
Chemistry
1 answer:
Kazeer [188]3 years ago
4 0
Hola amigo como estas? is the answer. i took the diagnostic
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zlopas [31]
Alveoli are tiny sacs within our lungs that allow oxygen and carbon dioxide to move between the lungs and bloodstream
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3 years ago
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assuming nitrogen behaves like an ideal gas, what volume would 14.0 g of nitrogen gas (N2) occupy at STP? the gas constant is 0.
dimaraw [331]

Answer:

V = 22.41 L

Explanation:

Given data:

Mass of nitrogen = 14.0 g

Volume of gas at STP = ?

Gas constant = 0.0821 atm.L/mol.K

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles= 14 g/ 14 g/mol

Number of moles = 1 mol

Volume of gas:

PV = nRT

1 atm × V = 1 mol × 0.0821 atm.L/mol.K  × 273 K

V = 22.41 atm.L / 1 atm

V = 22.41 L

4 0
3 years ago
5.0 x 10^24 molecules equal
Ratling [72]
<span>4.999999999999999e</span>+<span>24 this is what i got on the calculator but i dont know if its right.</span>
8 0
3 years ago
1.5mol C3H8 from C3H8+5O2--&gt;3CO2+4H2O .how many grams of carbon dioxide are produced
koban [17]

Answer:

\large \boxed{\text{200 g CO}_{{2}}}

Explanation:

We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

Mᵣ:                                 44.01

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:    1.5

1. Calculate the moles of CO₂

The molar ratio is 3 mol  CO₂:1 mol C₃H₈

\rm  \text{Moles of CO}_{2} = \text{1.5 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} =\text{4.5 mol CO}_{2}

2. Calculate the mass of CO₂.

\text{Mass of CO}_{2} = \text{4.5 mol CO}_{2}  \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO$_{2}$}} = \textbf{200 g CO}_{\mathbf{2}}\\\text{The reaction will form $\large \boxed{\textbf{200 g CO}_{\mathbf{2}}}$}

3 0
3 years ago
Please help this is due today! 5-11-2021
Licemer1 [7]

Answer:

- The chemical reaction is not balanced. There is two oxygens on the reactant's side while there's only one oxygen on the products side.

- I would not say it's following the law of conservation of mass as it's not a balanced equation.

- To balance this equation, you would need to add the coefficient of '2' to Magnesium (Mg) on the reactants side, and add the coefficient of '2' to the products side.  This would make it so that there's 2 Mg's and 2 O's on both the reactant's side and products side.

edit: I hope this helped you in some way. ^^

8 0
2 years ago
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