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3 years ago

If a liquid has a density of 1200 g/l what is it’s density in charge/ml

Chemistry

1 answer:

Juliette [100K]3 years ago

5 0

Answer:- $1.2\frac{g}{mL}$

Solution:- The given density is $1200\frac{g}{L}$ and it asks to convert it to $\frac{g}{mL}$ .

Here, we could notice that only volume unit is changing ad we know that, 1 L = 1000 mL. Let's make the set up as:

$1200\frac{g}{L}(\frac{1L}{1000mL})$

= $1.2\frac{g}{mL}$

So, the density is $1.2\frac{g}{mL}$ .

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Electromagnetic waves can transfer with or without blank

velikii [3]

Answer:

Molecules

Explanation:

Electromagnetic waves are not like sound waves because they do not need molecules to travel. This means that electromagnetic waves can travel through air, solid objects and even space.

-Alexis

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3 years ago

Read 2 more answers

What happens in the artificial transmutation of an element? Include an example.

Mice21 [21]

What happens in the artificial transmutation is that the nucleous is bombarded with high energy particles which we can describe as kinetic energy and the idea for them is to induce what we call transmutation. Also what happens is that the high energy particles are accelerated. One of the examples is when nitrogen is transformed into hydrogen by combining its nucleous with an alpha particle

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3 years ago

For the following reaction, 9.30 grams of glucose (C6H12O6) are allowed to react with 13.8 grams of oxygen gas. glucose (C6H12O6

amid [387]

Answer:

13.7 g of CO₂

Limiting reactant: C₆H₁₂O₆

3.81 g of O₂

Explanation:

We convert the mass of the reactants to moles, in order to find out the limiting reactant and the excess reagent

9.30 g / 180 g/mol = 0.052 moles of glucose

13.8 g / 32 g/mol = 0.431 moles of oxygen

The equation is: C₆H₁₂O₆(s) + 6O₂ (g) → 6CO₂ (g) + 6H₂O (l)

Ratio is 1:6. Let's consider this rule of three:

1 mol of glucose reacts with 6 moles of oxygen

Then, 0.052 moles of glucose must react with (0.052 . 6) /1 = 0.312 moles

We have 0.431 moles of oxygen and we only need 0.312 moles. This means that an amount of oxygen still remains after the reaction is complete:

0.431 - 0.312 = 0.119 moles. We convert the moles to mass:

0.119 mol . 32 g / 1mol = 3.81 g

In conclussion, the limiting reactant is the glucose.

6 moles of oxygen react with 1 mol of glucose

0.431 moles of O₂ will react with (0.431 . 1) /6 = 0.072 moles of glucose

We only have 0.052 moles, so it is ok to say, that glucose is the limiting cause we do not have enough glucose.

Let's verify, the maximum amount of carbon dioxide that can be formed:

1 mol of glucose can produce 6 moles of CO₂

Therefore 0.052 moles of glucose will produce (0.052 . 6) /1 = 0.312 moles

We convert the moles to mass → 0.312 mol . 44 g /1 mol = 13.7 g

6 0

3 years ago

If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?

sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$2HgO\rightarrow 2Hg+O_2$