2 rational numbers are C. 2.777 and D. -7/3
a rational number<span> is any </span>number<span> that can be expressed as the quotient or fraction p/q of two integers
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as you know 0.7777 (7 repeat) = 7/9
so 2.777(7 repeat) = 2 7/9
5 times 2 plus .015 times 2
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
400 800 1200 1600 2000 is anwser
Answer:
No
Step-by-step explanation:
The exponents are too far apart for a +2 to make a difference.
