hydrogen and oxygen atoms
Explanation:
this is because they are non metals and there will be sharing of electrons between the two atoms forming the bond
The empirical formula : MnO₂.
<h3>Further explanation</h3>
Given
632mg of manganese(Mn) = 0.632 g
368mg of oxygen(O) = 0.368 g
M Mn = 55
M O = 16
Required
The empirical formula
Solution
You didn't include the pictures, but the steps for finding the empirical formula are generally the same
- Find mol(mass : atomic mass)
Mn : 0.632 : 55 = 0.0115
O : 0.368 : 16 =0.023
- Divide by the smallest mol(Mn=0.0115)
Mn : O =

The empirical formula : MnO₂
Answer:
8.324 g
Explanation:
First we <u>convert 750.0 mL into L</u>:
- 750.0 mL / 1000 = 0.750 L
Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.100 M * 0.750 L = 0.075 mol
Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:
- 0.075 mol * 110.98 g/mol = 8.324 g