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Stels [109]
3 years ago
12

What phase change is endothermic

Chemistry
2 answers:
LenKa [72]3 years ago
5 0
Sublimation is endothermic
Semenov [28]3 years ago
5 0

Answer:

Vaporization

Explanation:

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When assigning electrons to orbitals, which would be the most likely 'address' for the next electron following the 5s2 electron?
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The answer is number 3, 4d1.
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Be sure to answer all parts. Nitric oxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO2), a dark brown gas: 2NO(g) +
notka56 [123]

<u>Answer:</u> NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is present in less amount and it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount.

For the given chemical reaction:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

We are given:

Moles of NO = 0.857 mol

Moles of oxygen = 0.498 mol

By stoichiometry of the reaction:

If 2 moles of NO reacts with 1 mole of oxygen gas.

So, 0.857 moles of NO will react with = \frac{1}{2}\times 0.857=0.4285mol of O_2

As, the given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, NO is considered as the limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

If 2 moles of NO produces 2 moles of nitrogen dioxide gas.

So, 0.857 moles of NO will produce = \frac{2}{2}\times 0.857=0.857mol of NO_2

Hence, NO is the limiting reagent in the given reaction and 0.857 moles of NO_2 will be produced.

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What is biodiversity?
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When liquid water changes into solid ice, it increases in ?
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when liquid water changes into solid ice, it increases in mass

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a flask was filled with SO2 at a partial pressure of 0.409 atm and O2 at a partial pressure of 0.601 atm. The following gas-phas
jarptica [38.1K]

Answer:

The equilibrium partial pressure of O2 is 0.545 atm

Explanation:

Step 1: Data given

Partial pressure of SO2 = 0.409 atm

Partial pressure of O2 = 0.601 atm

At equilibrium, the partial pressure of SO2 was 0.297 atm.

Step 2: The balanced equation

2SO2 + O2 ⇆ 2SO3

Step 3: The initial pressure

pSO2 = 0.409 atm

pO2 = 0.601 atm

pSO3 = 0 atm

Step 4: Calculate the pressure at the equilibrium

pSO2 = 0.409 - 2X atm

pO2 = 0.601 - X atm

pSO3 = 2X

pSO2 = 0.409 - 2X atm = 0.297

 X = 0.056 atm

pO2 = 0.601 - 0.056 = 0.545 atm

pSO3 = 2*0.056 = 0.112 atm

Step 5: Calculate Kp

Kp = (pSO3)²/((pO2)*(pSO2)²)

Kp = (0.112²) / (0.545 * 0.297²)

Kp = 0.261

The equilibrium partial pressure of O2 is 0.545 atm

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3 years ago
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