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sasho [114]
3 years ago
7

Help me plzzzzzzzzz solve for x

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

7) \frac{x+20}{x}=\frac{46}{30}

30(x+20)=46x

30x+600=46x

46x-30x=600

16x=600

x=75/2

x=37.5

---------------------

8) \frac{10}{3x+1} =\frac{22}{7x-1}

10(7x-1)=22(3x+1)

70x-10=66x+22

70x-66x=22+10

4x=32

x=\frac{32}{4}

x=8

<u>---------------------</u>

hope it helps...

have a great day!!

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Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =&#10;\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
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<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
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4 years ago
Will give brainlst <br> Have a nice day
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Answer:

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3 years ago
(NEED THE ANSWER AS SOON AS POSSIBLE)
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Answer: 42 - 8x

Step-by-step explanation:

Here is the complete question:

Jessica had $15. She bought 3 apples for x dollars each. Levi had $27 and bought 5 apples for x dollars each. Which expression represents how much money both Jessica and Levi have left altogether?

Select one:

27 – 5x

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From the question, Jessica had $15. She bought 3 apples for x dollars each. This means she had:

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27 - (5 × x) = 27 - 5x

The amount they'll have altogether will be the addition of their amount left. This will be:

15 - 3x + 27 - 5x

= 15 + 27 - 3x - 5x

= 42 - 8x

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Answer:

Thanks

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