<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
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Pass the incognito "4x" to the first term, changing the signal when changing sides.
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simplify by (-1)
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</span></span><span>Substitute in equation (I) to find the value of "Y".
</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3

Answer:

First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
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4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
Area = Length x Width
Substituting the given values:
16S^2 t = 8St^2 x Width
Manipulating for Width:
Width = 16S^2 t / <span>8St^2
Rewriting the squared terms in simplified form :
</span>Width = 16 x S x S x t / <span>8 x S x t x t
</span>Cancelling the like terms
Width = 16 x S / <span>8 x t
</span>Cancelling the numeric terms :
Width = 2S / <span>t</span>
First we have to find out the common number of them.
For that purpose, the first number should be divided by next number.
100/20 = 5
20/4 = 5
4/0.8 = 5
we have found that 5 is the common number.
0.8/5 = 0.16
therefore the answer is c