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dezoksy [38]
3 years ago
8

student borrows $65,000 for business school at 8.5% stated annual interest with monthly repayment over 8 years. Consider this as

a loan with no payments or interest during school so that the problem structure is equivalent to a standard loan received one period before the first payment. Suppose that to better match expected student salary growth over time, the loan is structured as a growing annuity with each monthly payment growing by 0.2% compared to the previous monthly payment. How much is the first monthly payment?
Mathematics
1 answer:
lawyer [7]3 years ago
5 0

Answer:

First\ monthly\ payment= $858.69

Step-by-step explanation:

From the Question we are told that

Borrows $65,000

Annual interest  8.5%

Monthly repayment over 8 years

Generally PV of annuity with growth is mathematically represented as

where PV is present value

PV of annuity with growth X= (P/ (r-g)) * (1- ((1+g)/(1+r))^n)

     \frac{P}{\frac{8\%}{y12-0.2\%} } *(1-((1+0.2\%)/(1+8.5\%/12))^(^8^*^1^2^)^)=65000

    196.7213115P* 0.384791918=65000

     196.7213115P=65000/0.384791918

    196.7213115P=168922.4668

     P= 168922.4668/196.7213115

    P= 858.6892063

First\ monthly\ payment= $858.69

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Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

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Answer:

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Step-by-step explanation:

The attachment completes the question

From the attachment,

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