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3 years ago

Word equation for k(s)+H2O(l) yield KOH(aq) + H2(g)

2 answers:

4 0

Two moles of potassium react with 2 moles of water to form two moles of potassium hydroxide and 1 mole of hydrogen gas. The number of moles of hydrogen gas produced is half the number of moles of water and potassium that react together.

The molar mass of...

AveGali [126]3 years ago

4 0

Answer: The word equation for the given chemical equation is given below.

Explanation:

Word equation is defined as the equation in which substances are written in word form and not in chemical formulas. The words "and" or "plus" means that one substance and another substance are both reactants or products.

For the given chemical equation:

$K(s)+H_2O(l)\rightarrow KOH(aq.)+H_2(g)$

The word equation for this follows:

$\text{(Potassium)}(s)+\text{Water}(l)\rightarrow \text{(Potassium hydroxide)}(aq.)+\text{Hydrogen gas}(g)$

Here, 1 mole of potassium metal reacts with liquid water to produce 1 mole of potassium hydroxide and 1 mole of hydrogen gas.

Hence, the word equation for the given chemical equation is given above.

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A group of students created a model showing a type of matter which of the following discribes what is shows by the model?

Lady_Fox [76]

Answer:

liquid

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3 years ago

Draw the product that valine forms when it reacts with excess CH3CH2OH and HCl followed by a wash with aqueous base.

-BARSIC- [3]

Answer:

Product: ethyl L-valinate

Explanation:

If we want to understand what it is the molecule produced we have to analyze the reagents. We have valine an amino acid, in this kind of compounds we have an amine group ( $NH_2$ ) and a carboxylic acid group ( $COOH$ ). Additionally, we have an alcohol ( $CH_3CH_2OH$ ) in the presence of HCl (a strong acid) in the first step, and a base ( $OH^-$ ).

When we have an acid and an alcohol in a vessel we will have an esterification reaction. In other words, an ester is produced. As the first step, the oxygen in the C=O (in the carboxylic acid group) would be protonated. In the second step, the ethanol attacks the carbon in the C=O of the carboxylic acid group producing a new bond between the oxygen in the ethanol and the carbon in the carboxylic acid. In step 3, a proton is transferred to produce a better leaving group ( $H_2O$ ). In step 4, a water molecule leaves the main structure to produce again the double bond C=O. Finally, a base ( $OH^-$ ) removes the hydrogen from the C=O bond to produce ethyl L-valinate

See figure 1

I hope it helps!

7 0

3 years ago

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Karolina [17]

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3 years ago

A package contains 1.33 lb of ground round. If it contains 29% fat, how many grams of fat are in the ground round? The book is s

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Answer:

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3 years ago

A student is trying to develop a model of an instant heat pack. What is the essential characteristic of the chemical reaction th

Lana71 [14]

The standard enthalpy of reaction should be negative.

<h3>What is enthalpy?</h3>

A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.

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Hence, option B is correct.

Learn more about enthalpy here:

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2 years ago