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Mademuasel [1]
2 years ago
12

Word equation for k(s)+H2O(l) yield KOH(aq) + H2(g)

Chemistry
2 answers:
KATRIN_1 [288]2 years ago
4 0
Two moles of potassium react with 2 moles of water to form two moles of potassium hydroxide and 1 mole of hydrogen gas.  The number of moles of hydrogen gas produced is half the number of moles of water and potassium that react together.

The molar mass of...

AveGali [126]2 years ago
4 0

<u>Answer:</u> The word equation for the given chemical equation is given below.

<u>Explanation:</u>

Word equation is defined as the equation in which substances are written in word form and not in chemical formulas. The words "and" or "plus" means that one substance and another substance are both reactants or products.

For the given chemical equation:

K(s)+H_2O(l)\rightarrow KOH(aq.)+H_2(g)

The word equation for this follows:

\text{(Potassium)}(s)+\text{Water}(l)\rightarrow \text{(Potassium hydroxide)}(aq.)+\text{Hydrogen gas}(g)

Here, 1 mole of potassium metal reacts with liquid water to produce 1 mole of potassium hydroxide and 1 mole of hydrogen gas.

Hence, the word equation for the given chemical equation is given above.

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7.66 Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water,
White raven [17]

Explanation:

(a) potassium oxide with water

K_2O(s)+H_2O(l)\rightarrow 2KOH(aq)

According to reaction,1 mole of potassium  oxide reacts with 1 mole of water to give 1 mole of potassium hydroxide.

(b) diphosphorus trioxide with water

P_2O_3(s)+3H_2O(l)\rightarrow 2H_3PO_3(aq)

According to reaction,1 mole of diphosphorus trioxide reacts with 2 moles of water  to give 2 moles of phosphorus acid.

(c) chromium(III) oxide with dilute hydrochloric acid,

Cr_2O_3(s)+6HCl(aq)\rightarrow 2CrCl_3(aq)+3H_2O(l)

According to reaction,1 mole of chromium(III) oxide reacts with 6 moles of hydrochloric acid to give 2 moles of chromium(III) chloride and 3 moles of water.

(d) selenium dioxide with aqueous potassium hydroxide

SeO_2 (s)+2KOH (aq)\rightarrow K_2SeO_3(aq)+H_2O(l)

According to reaction,1 mole of selenium dioxide reacts with 2 moles of potassium hydroxide to give 1 mole of potassium selenite and 1 mole of water.

6 0
3 years ago
What is the acknowledgment to ''Do all liquids evaporate at the same rate?'
natita [175]
<span>'Do all liquids evaporate at the same rate
 that would be false

</span>
4 0
2 years ago
When most liquids freeze, explain what happens to the motion and the space between the atoms.
KiRa [710]

Answer:

atoms relative motion slow down and begin to vibrate in place

8 0
2 years ago
At 700 K, the reaction 2SO2(g) + O2(g) &lt;====&gt; 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f
nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

  • If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.
  • If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.
  • If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }

Q=\frac{10^{2} }{0.10^{2} *0.10}

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

3 0
2 years ago
From what you've learned so far, how is molecular structure related to smell?
Sidana [21]

Answer:

Changing the shape of the molecules that create fragrances in a flower or fruit may influence our perception of their smell. The reaction pattern produced, olfactory code, is sent as a signal to the brain, which which is how you smell things.

Explanation:

7 0
3 years ago
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