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Marizza181 [45]
4 years ago
14

( WILL MARK BRAINLIEST!!!!!!!!!) What is the result of increasing the temperature of an equilibrium system in which the forward

reaction is exothermic?
Group of answer choices

More products and fewer reactants

Fewer reactants and products

More reactants and products

More reactants and fewer products
Chemistry
1 answer:
kirill [66]4 years ago
4 0

Answer:

More reactants and fewer products

Explanation:

If reaction is exothermic it add heat to the environment, so when we add more heat the reaction will move in opposite direction. So, more reactants and fewer products will be formed.

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Identify the reactants in the equation: 6C0, + 6H2O - CHUO+ 60,
Effectus [21]

Answer:

The correct answer is d. 6H20 + 6CO2.

The reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

Explanation:

5 0
3 years ago
You titrated a 25.00 mL solution of 0.02 M oxalic acid with a freshly prepared solution of KMnO4. If it took 42.32 mL of this so
RideAnS [48]

Answer:

This is a Redox Titration reaction and the overall ionic equation is given as follows;

2 MnO⁴⁻ + 5C₂O₄ ²⁻+ 16H+  →  2Mn²⁺ + 10CO₂ + 8H₂O

From here, we could see that the stoichiometry ratio of KMnO₄ and oxalic acid = 2:5

To calculate the molarity  of KMnO₄, we will use the following equation.

x₁M₁V₁= x₂M₂V₂                                      (1)

Where,

x₁ = 2, stoichiometry number of KMnO₄ in the balanced reaction

x₂ = 5,  stoichiometry number of C₂O₄ in the balanced reaction

M₁ and M₂  are the molarities of oxalic acid and KMnO₄ solutions

V1  and V2  are the volumes of oxalic acid and KMnO₄ solutions.

Making M₂, the subject of the formula and substituting the given values, we have,

2M₁V₁ = 5M₂V₂, M₂=2M₁V₁ / 5V₂

= = 2x0.02Mx25mL/ 5x42.32mL

M₂=0.0047M

Hence, the molarity of the KMnO4 at endpoint =0.0047M

5 0
4 years ago
he Lewis structure for CO molecule contains Group of answer choices one double bond, one single bond, and twelve nonbonding elec
zimovet [89]

Answer:

One triple bond and four non bonding electrons

Explanation:

In considering the lewis structure of carbon monoxide, we must remember that the molecule contains a total of ten valence electrons. Four are the valence electrons that are present on the valence shell of carbon while six are the valence electrons on oxygen. Some of these valence electrons participate in bonding in the CO molecule.

Out of the six valence electrons on oxygen, two valence electrons participate in bonding with carbon while the other four electrons remain localized on the oxygen atom as two lone pairs of electrons.

Hence there are four nonbonding electrons in the lewis structure of CO as well as one triple bond.

6 0
3 years ago
Is O2 polar or nonpolar
PIT_PIT [208]

Answer: it is nonpolar

4 0
3 years ago
If an object has a density of 25 g/cm and a mass of 100 grams, what is its volume? O 40 cm3 0.25 cm 4 cm3 125 cm3​
xz_007 [3.2K]
<h3>Answer:</h3>

4 cm³

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Chemistry</u>

<u>Gas Laws</u>

Density = Mass over Volume

  • D = m/V
<h3>Explanation:</h3>

<u>Step 1: Define</u>

D = 25 g/cm³

m = 100 g

<u>Step 2: Solve for </u><em><u>V</u></em>

  1. Substitute variables [D]:                    \displaystyle 25 \ g/cm^3 = \frac{100 \ g}{V}
  2. Multiply <em>V</em> on both sides:                  \displaystyle V(25 g/cm^3) = 100 \ g
  3. Isolate <em>V</em>:                                            \displaystyle V = 4 \ cm^3
8 0
3 years ago
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