Answer:
One 200 is bigger than 100
Explanation:
To solve this problem we will apply the concept related to the electric field defined from the laws of Coulomb. For this purpose we will remember that the electric field is equivalent to the product of the Coulomb constant due to the change of the charge over the squared distance, mathematically this is
Here,
k = Coulomb's constant
r = Distance from center of terminal to point where electric field is to found
q = Excess charge placed on the center of terminal of Van de Graff's generator
Replacing we have that,
Therefore the electric field is 
Answer:
for one they will stay there. And another thing it will do is collect rust pretty much destroying it.
Explanation:
(a) The projectile's velocity at the highest point of its trajectory is 51.96 m/s.
(b) The maximum height reached by the projectile is 45.92 m.
<h3>
Projectile velocity at the highest point of trajectory</h3>
At the highest point of trajectory the vertical component of the velocity will be zero will the horizontal component will remain constant.
Vxi = Vxf = Vcosθ = 60 x cos30 = 51.96 m/s
<h3>Maximum height of the projectile</h3>
The maximum height reached by the projectile is calculated as follows;
H = u²sin²θ/2g
H = (60² x (sin30)²)/(2 x 9.8)
H = 45.92 m
Learn more about projectile here: brainly.com/question/24216590
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Answer:
he phase difference is π the destructive interference and the lujar is a still or silent place
Explanation:
This is a sound interference exercise where the amino difference is equal to the phase difference of the sound.
Δr / λ = ΔФ / 2π
Let's find the path difference
r₁ = 4m
r₂ = √ (4² + 3²) = 5 m
Δr = r₂ - r₁
Δr = 5-4 = 1m
Let's find the wavelength of the sound
v = λ f
λ = v / f
λ = 340/170
λ = 2m
Let's find the phase difference between the two waves
ΔФ = Δr 2π / λ
ΔФ = 1 2π / 2
ΔФ = π
Since the phase difference is π the destructive interference and the lujar is a still or silent place
