Circumference of a circle can be calculated if the radius or the diameter is given.
<u>Explanation</u>:
- Circumference or the perimeter of a circle can be calculated if the radius or the diameter of the circle is given.
- This is calculated by the formula - 2 * pi * r (if radius is given) and pi * d (if diameter is given) where pi = 3.14, r = radius and d = diameter
- This calculation is based on the fact that the circumference is three and a little more times that of the radius. Since the diameter is double that of the radius, when the diameter is given formula becomes pi*d.
The answer is D. All of these
Answer:
The total number of Cl atoms in 150mL of liquid CCl4 is 3.73*10²⁴.
Explanation:
First you must determine the mass of CCL4 present in 150mL of CCl4. Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance, whose expression for its calculation is the quotient between the mass of a body and the volume it occupies:

In this case, the density value of d = 1.589 g/mL. Then, being the volume equal to 150 mL, the value of the mass can be calculated as:
mass= density*volume
mass=1.589 g/mL * 150 mL
mass= 238.35 g
Now, being the molar mass of CCl4 154 g/mol, the number of moles that 238.35 g represents is calculated as:

moles= 1.55
1 mole of the compound CCl4 contains 4 moles of Cl. Then, using a simple rule of three, it is possible to calculate the number of moles of Cl that 1.55 moles of CCl4 contain:

moles of Cl= 6.2
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance. In this case it can be applied as follows: if 1 mole of Cl contains 6.023*10²³ atoms, 6.2 moles of Cl how many atoms does it contain?

atoms of Cl= 3.73*10²⁴
<u><em>The total number of Cl atoms in 150mL of liquid CCl4 is 3.73*10²⁴.</em></u>
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.