Ask question

Ask question

All categories

3 years ago

12

How does the gravitational force exerted on earth by the sun with that exerted by the moon

1 answer:

kaheart [24]3 years ago

6 0

The gravitational forces between the sun and the Earth
are about 176 times stronger than the gravitational forces
between the moon and the Earth.

For the calculation, see the answer to the other time you
posted this question.

Wow ! What does that say about the tides ?
I'm not sure just now.

You might be interested in

If a non-rotating object has no acceleration, then we can say for certain that it is:__________

EleoNora [17]

We may be positive that an object is in mechanical equilibrium if it is not rotating and experiences no acceleration.

<h3>What is mechanical equilibrium?</h3>

There are numerous other definitions for mechanical equilibrium that are all mathematically comparable in addition to the definition in terms of force. A system is in equilibrium in terms of momentum if the component motions are all constant. If velocity is constant, the system is in equilibrium in terms of velocity. When an item is in a state of rotational mechanical equilibrium, its angular momentum is preserved and its net torque is zero. More generally, equilibrium is reached in conservative systems at a configuration space location where the gradient of the potential energy concerning the generalized coordinates is zero.

To learn more about mechanical equilibrium, visit:

<u>brainly.com/question/14246949</u>

#SPJ4

6 0

1 year ago

You're driving a vehicle of mass 1350 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 71 m

sergey [27]

Answer:

$v=12.65\ m.s^{-1}$

Explanation:

Given:

mass of vehicle, $m=1350\ kg$

radius of curvature, $r=71\ m$

coefficient of friction, $\mu=0.23$

<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>

$m.\frac{v^2}{r} =\mu.N$

where:

$\mu=$ coefficient of friction

$N=$ normal reaction force due to weight of the car

$v=$ velocity of the car

$1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)$

$v=12.65\ m.s^{-1}$ is the maximum velocity at which the vehicle can turn without skidding.

5 0

3 years ago

Identify the three types of isometric transformations. A. reflection, rotation, translation B. reflection, rotation, dilation C.

inessss [21]

<span>reflection, rotation, translation</span>

4 0

3 years ago

Why is it that, in a spoon, you can see yourself upside down? Bamboozled me for years.

Delvig [45]

Here is your answer.

6 0

3 years ago

A certain spring stores 10.0J of potential energy when it isstretched by 2.00cm from its equilibrium position.How much potential

qaws [65]

Answer:

Answered

Explanation:

x= 0.02 m

E_p= 10.0 J

E_p= 0.5kx^2

10= 0.5k(0.02)^2

solving we get

K= 50.0 N/m

Now

E'_p= 0.5kx'^2

E'_p= 0.5×50×(0.04)^2

E'_p=40 J

b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both

c) 20 J = 0.5×50,000×x^2

solving

x= 0.028 m

d) k is 50.0 N/m from above calculation

3 0

3 years ago