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3 years ago

10

Calculate the kinetic energy of a 20-kg sled moving 28.0 m/s. Show your work in the space to the right.

1 answer:

suter [353]3 years ago

5 0

Answer:

7840

Explanation:

K.e=1/2mv^2

=1/2(20)(28.0)^2

=7840J

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Ph11_UnitPacket2019

frozen [14]

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4 years ago

Read 2 more answers

7) A long straight wire of radius 1.00x10-3 m (1 mm) carries uniform current density J such that the magnetic field at the edge

Vedmedyk [2.9K]

Answer:A)0.5 and 2 mm

Explanation:

Given

radius R of wire is 1 mm

magnetic Field at edge(surface) $=10^{-5} T$

Magnetic Field at a distance r' from Center is $B'=5\times 10^{-6} T$

and we know

$B=\frac{\mu _0I}{2\pi r}$

where $I= current$

$\mu _o=$ Permeability of free space

$r=$ distance from center

For $r=R$

$10^{-5}=\frac{\mu _0I}{2\pi R}$ ---1

For $r=r'$

$5\times 10^{-6}=\frac{\mu _0I}{2\pi r'}$ ---2

Divide 1 and 2

$\frac{10^{-5}}{0.5\times 10^{-5}}=\frac{r'}{R}$

$r'=2 R=2 mm$

If r is inside the wire then

$B=\frac{\mu _0rI}{2\pi R^2}$

for $r=R$

$10^{-5}=\frac{\mu _0R\cdot I}{2\pi R^2}$ ---3

for $r=r"$

$5\times 10^{-6}=\frac{\mu _0r"I}{2\pi R^2}$ ----4

Divide 3 and 4

$2=\frac{R}{r"}$

$r"=0.5 mm$

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3 years ago