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Elena L [17]
3 years ago
11

A basketball player scored 26 points in one game. In basketball, some baskets are worth 3 points, some are worth 2 points, and f

ree-throws are worth 1 point. He scored four more 2-point baskets than he did 3-point baskets. The number of free-throws equaled the sum of the number of 2-point and 3-point shots made. How many free-throws, 2-point shots, and 3-point shots did he make?
Mathematics
2 answers:
Vsevolod [243]3 years ago
5 0

Answer:

3 points = 2

2 points = 6

1 point = 8

Step-by-step explanation:

Given that:

Total point scored = 26

Let number of 3 point basket = x

Number of 2 point basket = x + 4

Number of free throws = x + x + 4 = 2x + 4

Hence,

Total 3 points = 3x

Total 2 points 2(x + 4)

Total free throw points = 2x + 4

3x + 2(x + 4) + 2x + 4 = 26

3x + 2x + 8 + 2x + 4 = 26

7x + 12 = 26

7x = 26 - 12

7x = 14

x = 2

Number of 3 points = x = 2

2 points = (x+4) = 2+4 = 6

1 point = (2x+ 4) = 2(2) + 4 = 8

Sever21 [200]3 years ago
4 0

Answer:

3 points = 2

2 points = 6

1 point = 8

Step-by-step explanation:

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A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
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Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

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So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

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\text{Probability}=\frac{1}{5}

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Answer:

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Step-by-step explanation:

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