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sattari [20]
3 years ago
15

A box contains 2 purple marbles, 2 blue marbles, 3 green marbles, and 5 red marbles. What is the probability of picking a green

marble?
Mathematics
2 answers:
kirza4 [7]3 years ago
5 0

Answer:

0.25

Step-by-step explanation:

The total number of marbles is 2 + 2 + 3+ 5 = 12

the number of green ones is 3

So the probability of green = 3/12 = 1/4 = 0.25

Katyanochek1 [597]3 years ago
5 0

Answer:

Red

Step-by-step explanation:

Because it was most pick the first time

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A rectangle has an area 18sq cm.id its length and width are wjole numbera.what is its greatest possible perimeter
makkiz [27]

Answer:

38cm

Step-by-step explanation:

1. The perimeter of a square can be found with the formula2 \times (width + length)

2. Since its length and width are whole numbers, it must be either

1 x 18,

2 x 9 or

3 x 6

3. Using the formula in step 1, we can found that the perimeter in these cases are

38

22

18

respectively

4. Compare those perimeter we found in previous step, it's obvious that the greatest is 38. Solved.

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Richard ate g out of 12 gumdrops. Write an expression that shows how many gumdrops Richard has left.
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An expression to show would be : g/12
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Step-by-step explanation:

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3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

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3 years ago
Eduardo thinks of a number between 1 and 20 that has exactly 5 factors.What number is he thinking of?
Leni [432]

Eduardo is thinking of the number  16 .
3 0
3 years ago
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