Answer: 6702.1
Explanation:
Volume of cylinder = πr^2h
= π(8^2)25
= 1600 π
Volume of cone = πr^2(h/3)
= π(8^2)(25/3)
= π (64)(25/3)
= (1600 π)/3
Add these two numbers
= 1600 π + (1600 π)/3
= (4800 π+ 1600 π)/3
= 6400 π/ 3
=6702.06≈6702.1
Answer:
x = 18
Step-by-step explanation:
b squared + x squared = 30 squared
A=43°
B=82°
c=28
1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
125°+C=180°
Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
C=55° (option B or C)
2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°
2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3
2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8
Answer: Option B) C=55°, b=33.8, a=23.3
Each pound cost $3.32
p pounds would cost = p*3.32 = 3.32p
Total cost C = $3.32p
I hope this explains it.
Answer: [0, 396]
Step-by-step explanation:
The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.
0 to 44 written in interval notation is [0,44].
The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.
A(t) = 9t
A = 9(44)
A = 396
With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.
0 to 396 written in interval notation is [0, 396].
