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Answer:</h2>
<u><em>Let m be the amount each mom can paint and d be the amount each daughter can paint.</em></u>
<u><em>On the first day, 8 mothers were painting so the mothers painted 8m square feet. 12 daughters also painted so the daughters painted 12d square feet. The total amount painted on the first day is then 8m+12d square feet. Since 220 square feet was painted on the first day, then 8m+12d=220. Dividing both sides by 4 gives a simplified equation of 2m+3d=55.</em></u>
<u><em>On the second day, 6 mothers were painting so the mothers painted 6m square feet. 8 daughters also painted so the daughters painted 8d square feet. The total amount painted on the second day is then 6m+8d square feet. Since 152 square feet was painted on the second day, then 6m+8d=152</em></u>
<u><em /></u>
<u><em>Multiply the first equation by -3 and then add it to the second equation to eliminate m and solve for d:</em></u>
<u><em>d=13</em></u>
<u><em>2m+3d=55</em></u>
<u><em>2m+3(13)=55</em></u>
<u><em>2m+39=55</em></u>
<u><em>2m=16</em></u>
<u><em>m=8</em></u>
<u><em>Therefore each mom painted 8 square feet and each daughter painted 13 square feet.</em></u>
118 handle bars tells us that there's 118 bikes
if all 118 bikes were regular bikes
118*2 = 236
we would be 33 wheels short
118*1 = 118
we would be 17 seats short
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if 101 of the bikes are regular and 17 are tandem
101*1 = 101
17*2 = 34
we would have the right amount of seats
101*2 = 202
17*2 = 34
202 + 34 = 236
we would be 33 wheels short.
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if 17 bikes are tandem, 33 are tricycle, and 68 are regular
17*2 = 34
33*3 = 99
68*2 = 136
we would have the right amount of wheels
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Answer:
There are 68 bicycles, 17 tandem bicycles, and 33 tricycles.
This question isn't hard, it just takes longer since it's based off of guess and check.
To simplify that expression you'll join like terms.
8x + 4 - 5
8x - 1
