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Kaylis [27]
3 years ago
5

Calculate the length of the circumference of a circle with diameter of 8cm

Mathematics
2 answers:
algol [13]3 years ago
6 0
The circumference of ANY circle is (pi) x (the circle's diameter).

So the circumference of THIS one is  8pi cm.

That's roughly  25.133 cm.  (rounded)
stiks02 [169]3 years ago
5 0
Multiply 8 with pi since the equation for circumference is 2pi(r), or d(pi). The answer is 25.13
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[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~ -9 &,& -1~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies 
\begin{cases}
\cfrac{-9+x}{2}=8\\\\
-9+x=16\\
\boxed{x=25}\\
-------\\
\cfrac{-1+y}{2} =14\\\\
-1+y=28\\
\boxed{y=29}
\end{cases}

\bf -------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~10 &,& 12~)
\end{array}\qquad
\\\\\\
\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies 
\begin{cases}
\cfrac{10+x}{2}=6\\\\
10+x=12\\
\boxed{x=2}\\
-------\\
\cfrac{12+y}{2} =9\\\\
12+y=18\\
\boxed{y=6}
\end{cases}
3 0
3 years ago
Examine the following system of inequalities.
lubasha [3.4K]

Answer:

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)

Step-by-step explanation:

we have

y > -x+4 ----> inequality A

The solution of the inequality A is the shaded area above the dotted line y=-x+4

The dotted line passes through the points (0,4) and (4,0) (y and x-intercepts)

and

y \leq -(1/2)^{x} +6 -----> inequality B

The solution of the inequality B is the shaded area above the solid line y=-(1/2)^{x} +6

The solid line passes through the points (0,5) and (-2,2)

therefore

The solution of the system of inequalities is the shaded area between the dotted line and the solid line

see the attached figure

Dotted linear inequality shaded above passes through (0, 4) and (4, 0). Solid exponential inequality shaded below passes through (negative 2,2) & (0,5)

7 0
3 years ago
Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?
Ne4ueva [31]
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
8 0
3 years ago
Can anybody help? Having a little trouble with this during quarantine...
kolbaska11 [484]
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6 0
3 years ago
Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?
Katyanochek1 [597]
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x  approach infinity
lim y = arccos 1/2 = 1.047
6 0
3 years ago
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