Ne(neon) has the highest ionization energy among the elements above.
Where are options? without that, i can’t help you sorry
Answer:
32.04°C will be the final temperature of the solution.
Explanation:
Moles of potassium chloride = 0.200 mol
MAs sof KCl= 0.200 mol × 74.5 g/mol= 14.9 g
Enthalpy of solvation of potassium nitrate =
![\Delta H_{solv}=17.1 kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H_%7Bsolv%7D%3D17.1%20kJ%2Fmol)
Energy released when 0.200 moles of KCl is dissolved in water = Q
![Q=17.1kJ/mol\times 0.200 mol=3.42 kJ=3420 J](https://tex.z-dn.net/?f=Q%3D17.1kJ%2Fmol%5Ctimes%200.200%20mol%3D3.42%20kJ%3D3420%20J)
(1 kJ = 1000 J)
Heat released on dissolving 0.200 moles of KCl is equal to heat absorbed by water = Q
Mass of solution , m= 80.0 g +14.9 g = 94.9 g
Specific heat of water = c = 4.184 J/g°C
Initial temperature of the water = ![T_1=23.4^oC](https://tex.z-dn.net/?f=T_1%3D23.4%5EoC)
Final temperature of the water = ![T_2=?](https://tex.z-dn.net/?f=T_2%3D%3F)
![Q=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
![3420 J=94.9g\times 4.184 J/g^oC\times (T_2-23.4^oC)](https://tex.z-dn.net/?f=3420%20J%3D94.9g%5Ctimes%204.184%20J%2Fg%5EoC%5Ctimes%20%28T_2-23.4%5EoC%29)
![T_2=32.04^oC](https://tex.z-dn.net/?f=T_2%3D32.04%5EoC)
32.04°C will be the final temperature of the solution.
Question 1 - A goes to B and D goes through E and out of C
Question 2 - A is left side D is right side
Question 3 -
A
B
D
Question 4 - it’s A no oxygen blood goes through A