A. 125+25+5+1 B. 25+5+1+1/5 C.1+1/5+1/25+1/125 D.1/125+1/5+5+125
1 answer:
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AC=x, BC=x√3, AB is a hypotenuse (look at the pic below)
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
AB=√(x²+(x√3)²)=√(x²+3x²)=√(4x²)=2x
<em>Thus, cosB is:</em>
cosB=(x√3)/(2x)=√3/2
Answer:
Equation: 4x = 128
Step-by-step explanation:
(Linear pair angles)
- -> (x + 52)° + (3x)° = 180°
- -> (4x + 52)° = 180°
- -> 4x + 52 = 180
- -> 4x = 180 - 52
- -> 4x = 128 ( This is the required equation)
- -> x = 128/4
- -> x = 32