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3 years ago

A. 125+25+5+1 B. 25+5+1+1/5 C.1+1/5+1/25+1/125 D.1/125+1/5+5+125

Mathematics

1 answer:

Amanda [17]3 years ago

4 0

Answer:

Step-by-step explanation:

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1 year ago

In a right triangle, the side opposite a 33 degree angle is 17 units. What is the length of the side adjacent to that angle to t

AnnyKZ [126]

Answer:

The length of the side adjacent to that angle is 26 units

Step-by-step explanation:

We are given

In a right triangle, the side opposite a 33 degree angle is 17 units

Firstly, we will draw diagram

we can use trig

$cot(33)=\frac{x}{17}$

now, we can solve for x

$x=17\times cot(33)$

$x=26.177$

So,

The length of the side adjacent to that angle is 26 units

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3 years ago

Which of the following exponential functions represent the graph?

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Answer:

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2 years ago

Find the ratios of 8 and 3 of the perimeters and of the areas ? please some one help me

vagabundo [1.1K]

I don't get what you are asking, please elaborate?

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2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

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3 years ago