All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
Greater than 1 because left side is a fraction less than 1 and right side is a number greater than 1.
The left side being a fraction less than 1 could only mean that you have to multiply a number greater than 1 to the other side. And since the other side is a number greater already than 1 then multiplying the left side to the right side must result in a number greater than 1.
-19m-19 = 4m-4m+19
-19m-19 = 0+19
-19m = 19+19
-19m = 38
m = 38÷(-19)
m = -2
Answer:
113
Step-by-step explanation:
we need to know how much Lou has first !
so we have to do 682 / 6 which = 113
then 113 / 4 = 28.2
28.2 is how much Lou has
so we will go back and multiply the 4
28.2 x 4 =113
Answer:
95+75=170 mph=speed at which the two trains are moving apart
travel time=distance/speed=374/170=2.2
How long will it take for the two trains to be 374 miles apart? 2.2 hrs
Step-by-step explanation:
