Answer:
D. 45.0 g
Explanation:
In present reaction, 1 mol of N2 react with 3 moles of H2 to generate 2 moles of NH3
Thus, 2 moles of NH3 ≡ 3 moles of H2
Therefore, 15 moles of NH3 ≡ (3×15)/2 = 22.5 moles of H2.
We know that, 1 mole of H2 ≡ 2 g
Therefore, 22.5 moles of H2 ≡ 2 × 22.5 = 45 g
Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion
No as neutral object will attract and be attracted by a positive and negative charge
hope that helps
(99% of the total mass). 49% of carbon, 44% of oxygen, 6% of hydrogen, 0.1-0.3% of nitrogen.
Answer:
1 mole of aluminum must contain 6.022⋅1023 atoms of aluminium → this is known as Avogadro's constant.
Explanation:
