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AVprozaik [17]
2 years ago
7

To sum up the question: why are some parts of the body more sensitive than others?

Chemistry
2 answers:
Leto [7]2 years ago
6 0

Answer: Some parts of the body are more sensitive than others because they each play an important role. For example, it hurts to bite your toungue because it has a lot of nerves.

Explanation:

natulia [17]2 years ago
5 0

Answer:

Some areas of the body are more sensitive than others because they have more nerve endings. It hurts when you bite your tongue because the sides of your tongue have a lot of nerve endings that are very sensitive to pain! The tongue, lips, and fingertips are the most touch-sensitive parts of the body.  The parts of your skin that need to be most sensitive like your fingertips and your lips have more receptor cells in them than others less sensitive areas.  The least sensitive skin on the human body is found in the heel area. This is because there are very few nerves in the heel to feel things. If there were too many nerves in our heels then walking would be far too painful.

Explanation:

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How many element are there on the periodic table?
givi [52]

Answer:118

Explanation: it’s right

5 0
2 years ago
Read 2 more answers
A sample of nitrogen gas is at a temperature of 50 c and a pressure of 2 atm. If the volume of the sample remains constant and t
Lilit [14]

Answer:

The new temperature of the nitrogen gas is 516.8 K or 243.8 C.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Where P = pressure, T = temperature, K = Constant

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 2 atm
  • T1= 50 C= 323 K (being 0 C= 273 K)
  • P2= 3.2 atm
  • T2= ?

Replacing:

\frac{2 atm}{323 K} =\frac{3.2 atm}{T2}

Solving:

T2*\frac{2 atm}{323 K} =3.2 atm

T2=3.2 atm*\frac{323 K}{2 atm}

T2= 516.8 K= 243.8 C

<u><em>The new temperature of the nitrogen gas is 516.8 K or 243.8 C.</em></u>

5 0
3 years ago
This is a science question for k12
bixtya [17]

Height of wave - amplitude

Higher the pitch - higher the frequency

Louder - higher the amplitude

bottom of the wave - trough

distance from crest to crest - wave length

top of the wave - crest

6 0
2 years ago
Read 2 more answers
BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
lapo4ka [179]

Steps/Answers:

Jot down the metal name.

Write the metal name ending in -idle.

Combine cation, annion names,

Hope This Helps!       Have A Nice Day!!

5 0
3 years ago
Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
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