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Rashid [163]
3 years ago
13

Can any one help me please

Mathematics
1 answer:
ELEN [110]3 years ago
4 0
The one that looks like a u is a quadratic function 

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An equation whose variables are polar coordinates is called a ____________
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An equation whose variables are polar coordinates is called a polar equation. These equation are characterized by an r as a function an angle. Polar equations can be written in rectangular coordinates by certain relationships. An example of a polar equation would be r = 2sin∅.
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3 years ago
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Find the value of x for m (arc AB)=23 and m(arc CD)=32 (the answer will be a decimal )
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5 0
3 years ago
Need help anything helps thanks
yKpoI14uk [10]

A binomial squared is written like

x^2+2ax+a^2

So, we have 2a=6 \iff a=3

So, we want to complete the square (x+3)^2 = x^2+6x+9

We can add and subtract 9 to write

x^2+6x = x^2+6x+(9-9) = (x^2+6x+9)-9 = (x+3)^2-9

5 0
3 years ago
Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
State if the two triangles are congruent. If they are state how you know.<br> Help me
deff fn [24]

Answer:

i think its the last option.

Step-by-step explanation:

its not the first one because they it can be proved using AAS (but that option isnt available)

You can't prove it with SSS or ASA without more info

AAA doesn't exist

theirfore it must be the last option.

3 0
2 years ago
Read 2 more answers
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