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3 years ago

What is the median of the data set?

2 answers:

7 0

B᷉᷈. 35

Y᷉᷈o᷉᷈u᷉᷈ p᷉᷈l᷉᷈a᷉᷈c᷉᷈e᷉᷈ t᷉᷈h᷉᷈e᷉᷈m᷉᷈ i᷉᷈n᷉᷈ n᷉᷈u᷉᷈m᷉᷈e᷉᷈r᷉᷈i᷉᷈c᷉᷈a᷉᷈l᷉᷈ o᷉᷈r᷉᷈d᷉᷈e᷉᷈r᷉᷈
T᷉᷈h᷉᷈e᷉᷈n᷉᷈ f᷉᷈i᷉᷈n᷉᷈d᷉᷈ t᷉᷈h᷉᷈e᷉᷈ m᷉᷈i᷉᷈d᷉᷈d᷉᷈l᷉᷈e᷉᷈ n᷉᷈u᷉᷈m᷉᷈b᷉᷈e᷉᷈r᷉᷈

Arturiano [62]3 years ago

6 0

First we need to arrange the numbers in this number set from smallest to biggest:17,18,24,27,31,39,42,47,55,65. Then there are 10 numbers in this number set. So when we calculate the median, we need to find the middle two numbers and calculate their average. So the median is (31+39)/2=35. SO the answer is B

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2 years ago

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3 years ago

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professor190 [17]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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Elden [556K]

Answer:

median=81

mode=73

range=24

Step-by-step explanation:

median: Middle number from lowest to highest crossing one-off from either side.

(73,73,79,81,88,97)

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8 0

3 years ago

Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.

8_murik_8 [283]

So for this function we will be using the quadratic formula, which is $x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a}$ , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

$x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92$

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0

3 years ago