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AleksAgata [21]
3 years ago
15

4. ____________________ is an equation that states a relationship between one quantity and one or more other quantities. *

Mathematics
1 answer:
telo118 [61]3 years ago
5 0
8. I think it’s parallel lines.
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Lia has already baked 2 cakes, and she can bake 1 cake with each additional stick of butter she buys. How many additional sticks
MariettaO [177]
She needs 45 more sticks of butter. This is because she already has two cakes, and 47-2=45. She can bake one more cake with each stick of butter, which means the answer is indeed 45. 
4 0
3 years ago
​A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and
sdas [7]

Answer: 24 plants

Step-by-step explanation:

1000 is not a perfect square.

31^2  < 1000 < 32^2

 

Required no. of trees = 32^2  − 1000

= 1024 − 1000

= 24

3 0
3 years ago
6.
ArbitrLikvidat [17]

Answer:

C. y = | x | – 13

Step-by-step explanation:

y = | x | – 13

Answer:

y = |x| -13

Step-by-step explanation:

recall for any function y = f(x), to translate the function vertically by any value "a", we simply have to add "a" to f(x).

If a is positive, then the graph is translated in the positive y-direction (i.e upwards), if a is negative, then the graph is translated in the negative y-direction (i.e downwards)

In our case , the graph is translated vertically by 13 units (i.e a = 13) and it is to be translated downwards (i.e negative)

hence we add a= -13 to the original function.

y = f(x) + (-13)

y = |x| + (-13)

y = |x| -13

3 0
2 years ago
Need help with problem 5, Thank you!<br><br><br> Sorry for the glare
MAXImum [283]

Answer:

x = 57

Step-by-step explanation:

A triangles degrees add up to 180

67 + 56 = 123

180 - 123 = 57

6 0
2 years ago
Use the definition of the derivative to differentiate v=4/2 pie r^3
nata0808 [166]

I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:

\displaystyle \frac{dV}{dr} = \lim_{h\to0} \frac{2\pi(r+h)^3-2\pi r^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{(r^3+3r^2h+3rh^2+h^3)- r^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{3r^2h+3rh^2+h^3}{h}

\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} (3r^2+3rh+h^2)

\displaystyle \frac{dV}{dr} = 2\pi \cdot 3r^2 = \boxed{6\pi r^2}

In Mathematica, you can check this result via

D[4/2*Pi*r^3, r]

3 0
2 years ago
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