I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.
First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:
1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)
2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).
3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).
4) Look at the fourth digit of your value. Imagine that between the two even smaller lines (0.36-0.37 and 3.52-3.53) that there is 10 smaller lines. Then, you can place your number according to your fourth digit. (So you'd place 0.365 at the 0.365 line and 3.521 at the 3.521 line)
Answer:
m∠y=50°
m∠x=50°
Step-by-step explanation:
we know that
The angles in matching corners are called <u><em>corresponding angles</em></u>. When the two lines are parallel Corresponding Angles are equal
so
m∠y=50° -----> by corresponding angles
and
The angles that are formed on opposite sides of the transversal and inside the two lines are <u><em>alternate interior angles</em></u>. When the lines are parallel, the alternate interior angles are equal.
so
m∠x=m∠y -----> by alternate interior angles
so
m∠x=50°
therefore
m∠y=50°
m∠x=50°
The answer to the question is 12,400
The answer to this would be x = 20
Answer:
The shaded region is 
.
Step-by-step explanation:
The area of a circle is defined by the multiplication of the square of its radius, or half its diameter, by pi, or simply 
.
15m is the radius of the large circle, and also the diameter of the smaller circles.
The area of the shaded region will be the subtraction of the area of the two smaller circles from the area of the larger circle.
As such:
