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3 years ago

PLEASE QUICK THE DEADLINE IS ALMOST OVERR!!!!!!

Mathematics

1 answer:

antoniya [11.8K]3 years ago

3 0

Answer:

I'm not smart hshddbkd

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Plot the value(s) on the number line where this function is equal to zero: fx) = (x + 5)(x - 1).

Anestetic [448]

Answer:

x = - 5, x = 1

Step-by-step explanation:

let f(x) = 0 , that is

(x + 5)(x - 1) = 0

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 1 = 0 ⇒ x = 1

Plot the points - 5 and 1 on the number line

8 0

2 years ago

7/12 - □ = 1/6 □ = ________

xz_007 [3.2K]

The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12

4 0

3 years ago

19.

vichka [17]

Answer:

168

Step-by-step explanation:

Sum the parts of the ratio, 6 + 7 = 13 parts

Divide the total number of students by 13 to find the value of one part of the ratio.

364 ÷ 13 = 28 ← value of 1 part of the ratio, thus

number of girls = 6 × 28 = 168

3 0

3 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$

8 0

4 years ago

Read 2 more answers

What is 7/10 equal

KatRina [158]

7/10 = 0.7
hope it helps

4 0

3 years ago

Read 2 more answers