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3 years ago

Which expression(s) are equivalent to the given expression?

Mathematics

2 answers:

jeka57 [31]3 years ago

7 0

Answer:

Step-by-step explanation:

You just need to multiply the first number by every number in the parantesis Take care bby :)))

mote1985 [20]3 years ago

6 0

Answer:

Step-by-step explanation:

B: 3x2x= 6x

3x6y= 18y

3x12=36

If there's more I apologize but that is all that I could find.

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gayaneshka [121]

Answer:

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2 years ago

A cube has sides of length 5 cm.

worty [1.4K]

5 x 5 = 25
25 x 6 = 150

150cm^2

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3 years ago

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A dentist selected 16 patients at random from a population of more than 1000 patients and asked them how many times the patient

Snezhnost [94]

Well, mode is the number that occurs most, so the answer would be 7, since that is the most appearing number.

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3 years ago

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Identify the vertex, the axis of symmetry, the maximum or minimum value, and the range of the parabola for y=x^2+6x+13

charle [14.2K]

Answer:

Step-by-step explanation:

First we can determine the x value of our vertex via the equation:

$x=\frac{-b}{2a}$

Note that in general a quadratic equation is such that:

$ax^2+bx+c$

In this case a,b and c are the coefficients and so a=1, b=6 and c=13.

Therefore we can determine the x component of the vertex by plugging in the values known and so:

$x=\frac{-b}{2a}=\frac{-6}{2(1)}=\frac{-6}{2}=-3$

Now we can determine the y-component of our vertex by plugging in the x-component to the equation and so:

$f(x)=x^2+6x+13\\\\f(-3)=(-3)^2+6(-3)+13\\\\f(-3)=4$

Therefore our vertex is (-3,4). Now in vertex our x component determines is the axis of symmetry so the equation for axis of symmetry is:

x=-3

Similarly, the y-component of our vertex is the minimum or maximum. In this case it is the minimum you can determine this because a is positive meaning that the parabola will point up, and so the equation for the minimum is:

y=4

The range of the formula is the smallest y-value meaning the minimum y=4 and all real numbers that are more than 4, mathematically:

Range = All real numbers greater than or equal to 4.

4 0

4 years ago

I geologist note is that the land alone at fault line moved 24.8 cm over the past 175 years on average how much did the land mor

zmey [24]

First, let's establish a ratio between these two values. We'll use that as a starting point. I personally find it easiest to work with ratios as fractions, so we'll set that up:

$\frac{24.8\ cm}{175\ years}$

To find the distance per year, we'll need to find the unit rate of this ratio in terms of years. The word unit refers to the number 1 (coming from the Latin root uni- ); a unit rate involves bringing the number we're interested in down to 1 while preserving the ratio. Since we're looking for the distance the fault line moves every one year, we'll have to bring that 175 down to one, which we can do by dividing it by 175. To preserve our ratio, we also have to divide the top by 175:

$\frac{24.8\ cm}{175\ years}\div \frac{175}{175} \approx 
\frac{0.14\ cm}{1\ year}$

We have our answer: approximately 0.14 cm or 1.4 mm per year

3 0

3 years ago