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2 years ago

11

suppose a farmer has six cows and each cow has six calves the first year, they all increase in the same propotion, to the end of

eight years, how many calves will the farmer have?( PLEASE MENTION THE STEPS AND FIFTY POINTS AND BRAINLIEST WILL BE GIVEN TO THE ONE WHO ANSWERS THIS QUESTION)

1 answer:

Sergio [31]2 years ago

4 0

Hi!

To solve this question you need to solve 7^8 x 6

7^8 = 5,764,801

5,764,801 x 6 = 34,588,806

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The function f is defined by f(x)=x^2-5 find f(2y)

Anuta_ua [19.1K]

$\bf f(x)=x^2-5\qquad \qquad f(2y)=(2y)^2-5\implies f(2y)(2^2y^2)-5
\\\\\\
f(2y)=4y^2-5$

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3 years ago

N ice cream shop uses the following ingredients to make 11 sundae. Ingredient Amount Ice cream 22 scoops Sprinkles 44 spoonfuls

zavuch27 [327]

16 sundaes

Because 22/11 = 2

32/2= 16

3 0

3 years ago

Read 2 more answers

A medium-sized (4-pound) sugar pumpkin should yield around 1½ cups of mashed pumpkin. So, if a 4-pound pumpkin will yield about

Greeley [361]

Answer: 948

Step-by-step explanation:

From the question, we are informed that 4-pound pumpkin will yield about 1.5 cups of mashed pumpkin (pumpkin puree).

Therefore, the number of cups of pumpkin puree that Steve Geddes' 2,528-pound pumpkin will yield will be:

= (2528/4) × 1.5

= 632 × 1.5

= 948 cups of pumpkin puree

4 0

2 years ago

Add and subtract rational numbers without common denominators. Show work! 1. 7/4 - 3/2 - 2/5 = 2. - 5/16 + 3/4 + 1/8 = 3. 3/4 -

alukav5142 [94]

$\dfrac{7}{4} - \dfrac{3}{2} - \dfrac{2}{5}$

$= \dfrac{7 \times 5}{4 \times 5} - \dfrac{3 \times 10}{2 \times 10} - \dfrac{2 \times 4}{5 \times 4}$

$= \dfrac{35}{20} - \dfrac{30}{20} - \dfrac{8}{20}$

$= \dfrac{35-30-8}{20}$

$= \dfrac{3}{20}$

---------------------------------------------------------------

$-\dfrac{5}{16} + \dfrac{3}{4} + \dfrac{1}{8}$

$= -\dfrac{5}{16} + \dfrac{3 \times 4}{4 \times 4} + \dfrac{1 \times 2}{8 \times 2}$

$= -\dfrac{5}{16} + \dfrac{12}{16} + \dfrac{2}{16}$

$= \dfrac{-5+ 12 + 2}{16}$

$= \dfrac{9}{16}$

---------------------------------------------------------------

$\dfrac{3}{4} - \dfrac{1}{3} - \dfrac{7}{12}$

$= \dfrac{3 \times 3}{4 \times 3} - \dfrac{1 \times 4}{3 \times 4} - \dfrac{7}{12}$

$= \dfrac{9}{12} - \dfrac{4}{12} - \dfrac{7}{12}$

$= \dfrac{9 - 4 - 7}{12}$

$= -\dfrac{2}{12}$

$= -\dfrac{1}{6}$

---------------------------------------------------------------

$\dfrac{2}{9} - \dfrac{2}{12} - \dfrac{2}{3}$

$= \dfrac{2}{9} - \dfrac{1}{6} - \dfrac{2}{3}$

$= \dfrac{2 \times 2}{9 \times 2} - \dfrac{1 \times 3}{6 \times 3} - \dfrac{2 \times 6}{3 \times 6}$

$= \dfrac{4}{18} - \dfrac{3}{18} - \dfrac{12}{18}$

$= \dfrac{4 - 3 - 12}{18}$

$= - \dfrac{11}{18}$

6 0

2 years ago

Using the given information write the equation of parabolas:

lana [24]

The general form of the equation we need to find is (x - h)^2 = 4p(y- k).

The center is the distance between the directrix and focus.

So, center (h, k) = (3, 3/2) .

P = distance from center to the focus and it just so happens to be 1.5.

We now plug everything into the formula given above.

(x - 3)^2 = 4(1.5)(y - 3/2)

(x - 3)^2 = 6(y - 3/2)

Done!

8 0

2 years ago