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Ivahew [28]
3 years ago
11

suppose a farmer has six cows and each cow has six calves the first year, they all increase in the same propotion, to the end of

eight years, how many calves will the farmer have?( PLEASE MENTION THE STEPS AND FIFTY POINTS AND BRAINLIEST WILL BE GIVEN TO THE ONE WHO ANSWERS THIS QUESTION)
Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Hi!

To solve this question you need to solve 7^8 x 6

7^8 = 5,764,801

5,764,801 x 6 = 34,588,806

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Lilit [14]

2x+3=17

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divide by 2 on each side

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What is the common ratio of 2, 10/3, 50/9
mojhsa [17]

The common ratio of 2, 10/3, 50/9 is \frac{10}{6}

<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take \frac{10}{3} and 2

\text { Then, common ratio }=\frac{\frac{10}{3}}{2}

\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}

Hence, the common ratio of the given series is \frac{10}{6}

6 0
3 years ago
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Dmitrij [34]
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