First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:
7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.
In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°
In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°
I'm sorry, but just now, I don't know how to do the
third triangle in the question.
Answer:
I'm gonna need to see the graph, sweetheart.
Answer:
b = 55°
Step-by-step explanation:
The angle at the centre is twice the angle on the circle subtended by the same arc, then
a = 0.5 × 110° = 55°
Angles on the circumference subtended by the same arc are congruent, so
b = a = 55°