Diagonals AC and BD form right angles at point M in parallelogram ABCD. Prove ABCD is a rhombus.
2 answers:
Answer:
B
Step-by-step explanation:
it just is man
Answer:
34
Step-by-step explanation:
Given, parallelogram ABCD intersect at E.
If the parallelogram has to be a rhombus,diagonals should bisect at 90 degree.
So,angle BEA=90degree
3x-12=90
3x=90+12=102
x=102/3=34
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
B
Step-by-step explanation:
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