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Nikitich [7]
3 years ago
9

(04.04)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

Step-by-step explanation:

11.04 I think

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Tell whether the relation is a function.
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The following set of points belong to a specific function: {(-3,15)(-2,17), (-1,11), (0,3),(1,-1), (2,5),(3,27)} Based on the se
adelina 88 [10]

Answer:

(a)Degree 3

(b)f(x)=x^3+2x^2-7x+3 .

Step-by-step explanation:

The function represented by the set of points: {(-3,15)(-2,17), (-1,11), (0,3),(1,-1), (2,5),(3,27)} has 2 turning points when plotted on a graph.

(a)Now, we know that the maximum number of turning points of a polynomial function is always one less than the degree of the function.

Therefore, the polynomial has a degree of 3

(b)A cubic function is one in the form f(x)=ax^3+bx^2+cx+d . where d is the y-intercept.

From the set of values, the y-intercept, d=3

Therefore, our polynomial is of the form:

f(x)=ax^3+bx^2+cx+3 .

\text{At } (-3,15), 15=a(-3)^3+b(-3)^2+c(-3)+3 \implies -27a+9b-3c=12\\\text{At } (-2,17), 17=a(-2)^3+b(-2)^2+c(-2)+3 \implies -8a+4b-2c=14\\\text{At } (-1,11), 11=a(-1)^3+b(-1)^2+c(-1)+3 \implies -a+b-c=8

Solving the three resulting equations simultaneously use a calculator), we obtain:

a=1, b=2, c=-7

Therefore, an equation of this function is:

f(x)=x^3+2x^2-7x+3 .

7 0
3 years ago
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