Iron and chlorine
For every iron there are 3 chlorine.
Answer:
because of the small soot particles
Answer: Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. The electrostatic attraction between the positives and negatives brings the particles together and creates an ionic compound, such as sodium chloride.
Answer:
P2= 125.26 Kpa
Explanation:
V1= 489.6 ml=0.4896L
V2= 750 ml= 0.750L
V1= 180 KPa= 180000 Pa
P2= ?
T1= 10 = 10 + 273.15 = 283.15K
T2= 28.7+273.15= 301.85K
180000Pa* 0.4896L/ 283.15K * 301.85K/0.75L
P2= 12526.28553
P2= 125.26 KPa
Explanation:
The given data is as follows.
Flow of chlorine (Q) = 
Amount of liter present per day is as follows.

It is given that dosage of chlorine will be as follows.
10 mg/l =
kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement =
kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.