All categories

3 years ago

What pressure will be exerted by 26g if CO2 at a temperature of 35C and a volume of 550ml?

Chemistry

1 answer:

STALIN [3.7K]3 years ago

3 0

Answer:

P = 28.5 atm

Explanation:

PV = nRT => P = nRT/V

P = Pressure = ?

n = moles of sample = mass/molar mass = 26g/44g·mol⁻¹ = 0.619 mole CO₂

R = gas constant = 0.08206 L·atm/mol·K

T = temperature in Kelvin = (35 + 273)K = 308K

V = volume in Liters = 550 ml = 0.550 L

Pressure (P) = nRT/V

= (0.619 mole)(0.08206 L·atm/mol·K)(308K)/(0.550 L) = 28.5 atm

You might be interested in

If 0.896 g of a gas occupies a 250 mL flask at 20°C and 760 mm Hg of pressure, what is the molar mass of the gas?

salantis [7]

Answer:

86.2 g/mol

Explanation:

Before you can find the molar mass, you first need to calculate the number of moles of the gas. To find this value, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (mmHg)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)

-----> T = temperature (K)

After you convert the volume from mL to L and the temperature from Celsius to Kelvin, you can use the equation to find the moles.

P = 760 mmHg R = 62.36 L*mmHg/mol*K

V = 250 mL / 1,000 = 0.250 L T = 20 °C + 273.15 = 293.15 K

n = ? moles

PV = nRT

(760 mmHg)(0.250 L) = n(62.36 L*mmHg/mol*K)(293.15 K)

190 = n(18280.834)

0.0104 = n

The molar mass represents the mass (g) of the gas per every 1 mole. Since you have been given a mass and mole value, you can set up a proportion to determine the molar mass.

$\frac{?grams}{1 mole} =\frac{0.896grams}{0.0104moles}$ <----- Proportion

$?grams(0.0104moles) = 0.896$ <----- Cross-multiply

$?grams = 86.2$ <----- Divide both sides by 0.0104

8 0

2 years ago

What two terms are used to describe the temperature at which solids and liquids of the same substance exist at the same time?

goldenfox [79]

Answer:

The answer is melting and freezing point.

Explanation:

5 0

3 years ago

A nuclear family consists of

inna [77]

A biological mother, A biological father and a child

3 0

3 years ago

The amount ofcalcium present in milk can be determined by adding oxalate to asample and measuring the massof calcium oxalate pre

Sauron [17]

<u>Answer:</u> The mass percent of calcium in milk is 0.107 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of calcium oxalate = 0.429 g

Molar mass of calcium oxalate = 128.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of calcium oxalate}=\frac{0.429g}{128.1g/mol}=0.0033mol$

The given chemical equation follows:

$Na_2C_2O_4(aq.)+Ca^{2+}(aq.)\rightarrow CaC_2O_4(s)+2Na^+(aq.)$

Sodium oxalate is present in excess. So, it is considered as an excess reagent. And, calcium ion is a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of calcium oxalate is produced from 1 mole of calcium ion

So, 0.0033 moles of calcium oxalate is produced from = $\frac{1}{1}\times 0.0033=0.0033mol$ of calcium ions