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valentinak56 [21]
3 years ago
6

Who is the intended audience?​

Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

From Middle school to college

storchak [24]3 years ago
3 0
Usually who you want your paper to be read by. For example “students need to spend less time on their phones” that is directed towards students. So students are the intended audience.
You might be interested in
what is the diffrence between displacement ans double displacement reactions write equations for these reactions
Lina20 [59]

Answer:

Single Displacement reaction  

In a displacement reaction, a more reactive element replaces a less reactive element from a compound.

Change in colour takes place with no precipitate forms.

Metals react with the salt solution of another metal.

Examples:

2KI + Cl2 → 2KCl + I2

CuSO4 + Zn → ZnSO4 + Cu

Double displacement reaction

In a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.

Precipitate is formed.

Salt solutions of two different metals react with each other.

Examples:  

Na2SO4 + BaCl2 → BaSO4 + 2NaCl

2KBr + BaCl2 → 2KCl + BaBr2

Hope this helps...Please Mark as Brainliest!!

8 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
3 years ago
Determine the number of grams of carbon-14 remaining in this sample at 17,100 years.
earnstyle [38]

Answer: I need help

Explanation:

8 0
3 years ago
Antoine Lavoisier burned metals in sealed jars. What is your prediction of his experimental results?
Aliun [14]

Answer:

The mass of the jar and contents remained the same after the metal was burned.

Explanation:

My prediction about the experimental results is that  the mass of the jar and contents remained the same after the metal was burned in the jar.

This is compliance with the law of conservation of mass which states that in a chemical reaction, matter is neither created nor destroyed by bonds are rearranged for new compounds to form.

  • In compliance with this law, it is expected that the mass of the jar and its content will remain the same before and after the reaction.
  • No new material was added and no material was removed from the jar.
8 0
3 years ago
Your chemistry lab partner is interested in studying how industrial chemicals can pollute the environment. What type of chemistr
Solnce55 [7]

Answer:

I would recommend them becoming an Analytical Chemist because Analytical Chemists examine and identify various elements and compounds to find out the composition, structure, and nature of substances and they determine the concentration of chemical pollutants in soil, water,and air. I would recommend taking inorganic, organic, analytical, and physical chemistry as well as computer science, physics, and environmental science

3 0
3 years ago
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