Hi there!
Here are some examples for you:
Two one step equations:
6x = 36
y + 5 = 10
Two equations containing fractions:
1/2x = 4
3/4y + 1 = 8
One equation using the distributive property:
2(x + 5) = 3
One equation with a decimal:
2.5x + 5 = 10
One real world problem that is solved by an equation:
At the beginning, I had 5 cups of flour. I made a batch of cookies. Now, I have 3.5 cups of flour. How much flour did I use?
5 - x = 3.5
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
Step-by-step explanation:
From the question we are told that:
Initial bearing ![\angle _1=21 \textdegree](https://tex.z-dn.net/?f=%5Cangle%20_1%3D21%20%5Ctextdegree)
Initial distance ![d_1=99miles](https://tex.z-dn.net/?f=d_1%3D99miles)
Final bearing ![\angle _2=227 \textdegree](https://tex.z-dn.net/?f=%5Cangle%20_2%3D227%20%5Ctextdegree)
Let
be the perimeter travailed
![\angle OAB=90+21=111 \textdegree\\\angle ABO=270-227=43 \textdegree](https://tex.z-dn.net/?f=%5Cangle%20OAB%3D90%2B21%3D111%20%5Ctextdegree%5C%5C%5Cangle%20ABO%3D270-227%3D43%20%5Ctextdegree)
Generally the equation for OB using sine rule is mathematically given by
![OB=99*\frac{sin111}{sin43}](https://tex.z-dn.net/?f=OB%3D99%2A%5Cfrac%7Bsin111%7D%7Bsin43%7D)
![OB=135.52miles](https://tex.z-dn.net/?f=OB%3D135.52miles)
Therefore the helicopter flight on the final leg of its journey is
![OB=135.52miles](https://tex.z-dn.net/?f=OB%3D135.52miles)